mubou 5 days ago

I know, but it's that last bit: it shouldn't be possible to bypass it. C# actually got itself into a similar issue despite being a proper static language, because when it added "nullable reference types" (where you can't assign null to a variable of type `Foo` unless it's explicitly typed as `Foo?`) they did it like TypeScript using purely static analysis to avoid having to change the language at a lower level (for compatibility).

Even though it works 99% of the time, just like in TS you can occasionally run into a bug because some misbehaving library handed you a null that it said can't be a null...

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Timon3 5 days ago

On the other hand, disallowing bypassing it limits what you can do. There's always a ceiling to what the compiler can figure out, and some very complex types can't be analysed statically right now. By allowing bypassing the system, I can still accurately type those functions and reap all the rewards, and I can make sure everything works by combining unit tests with type unit tests. If bypassing was disallowed, I'd be more limited in what I can express.

yencabulator 4 days ago

Safety bypasses should be opt-in, case by case, and very explicit. For example, Rust's `unsafe` allows bypassing any limitation the language safety imposes on you normally, but all code not explicitly labeled unsafe is always in the very very safe mode.

Even inside the Typescript rules, `as` is a ridiculously dangerous timebomb.

Typescript is 100% about "convenience" and write-lots-of-code-now style of productivity, ~0% about safety or long-term maintainability.

Timon3 4 days ago

What's the big difference between `unsafe` and `as` regarding explicit labelling? Both are opt-in and explicit. As the user of a function, you don't see either from the outside. If you don't like `as`, it's fine to use a linter to disallow it.

yencabulator 4 days ago

The difference is that in everyday Typescript you end up using `as`, so it's presence is not a blaring alarm.

Grepping a real world codebase that would not be `unsafe` in Rust:

  event as CustomEvent<T>

  const errorEvent = event as ErrorEvent;

  const element = getByRole("textbox");
  expect(element).toBeInstanceOf(HTMLInputElement);
  const input = element as HTMLInputElement;

  const element = parent.firstElementChild as HTMLElement;

  type ItemMap = Map<Item["id"], Item>;
  ...
  new Map() as ItemMap

  const clusterSource = this.map.getSource(sourceName) as GeoJSONSource;

  [K in keyof T as T[K] extends Fn ? K : never]: T[K];

  target[type] as unknown as Fn<...

  export const Foo = [1,2,3] as const;
and on it goes. Typescript normalizes unsafe behavior.

Timon3 4 days ago

Many, if not most, of these occurrences can be made safe. It's very rare that I need `as`, and even more rare that I can't actually check the relevant properties at runtime to ensure the code path is valid.

It's on you to ensure that you don't misuse `as`. If I could choose between current TS, and a "safer" one that's less expressive in complex cases, I'd choose the current one any day of the week.

yencabulator 4 days ago

"Typescript can be made safe" is the "C++ has a subset that is good" argument. Meh.

Timon3 4 days ago

Almost every language has some way to do stupid things. Say you're working in C# - you can forcefully cast almost anything to almost anything else, just like in TS. So according to you, C# is just as bad as TS in this respect, right?

neonsunset 4 days ago

You can only do this with `unsafe { }` or `Unsafe.As/.BitCast`. Casts from/to `object` are type-safe even though may not be very user-friendly or good use of the type system in general.

yencabulator 4 days ago

If that's a thing commonly needed for basic operations like letting your event handler actually access the event details, then very much yes.

Sane languages have a downcast mechanism that doesn't pretend it succeeds every time.

Timon3 4 days ago

Weird, I don't need to do that.

Also weird that Typescript has exactly the mechanism you're talking about. Why are you acting like it doesn't?