Reading their readme:
> Licensed under either of
> Apache License, Version 2.0 (LICENSE-APACHE or https://www.apache.org/licenses/LICENSE-2.0)
> MIT license (LICENSE-MIT or https://opensource.org/licenses/MIT)
> at your option.
I see this now and then, but it makes me wonder, why would I pick in this case Apache over MIT? Or is this software actually Apache licensed, but the developer is giving you greenlight to use it under the terms of the MIT? But at that point I don't get why not just license it all under MIT to begin with...
Per the Rust FAQ [1]:
> The Apache license includes important protection against patent aggression, but it is not compatible with the GPL, version 2. To avoid problems using Rust with GPL2, it is alternately MIT licensed.
The Rust API guidelines also recommend the same: https://rust-lang.github.io/api-guidelines/necessities.html#...
[1]: https://github.com/dtolnay/rust-faq#why-a-dual-mitasl2-licen...
From my perspective (as the author of Graft) my goal was to be open source and as compatible as possible with the Rust ecosystem. Hence the choice to dual license.
Thank you! That is helpful, and understandable from that context. I to try to follow the best standards surrounding the language I use for a given project.
One thing I can think of is that Apache gives you a patent grant and MIT doesn't